x^2+14x=1040

Solution for x^2+14x=1040 equation:

x^2+14x=1040

We move all terms to the left:

x^2+14x-(1040)=0

a = 1; b = 14; c = -1040;
Δ = b2-4ac
Δ = 142-4·1·(-1040)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-66}{2*1}=\frac{-80}{2}
=-40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+66}{2*1}=\frac{52}{2}
=26
$